LTC6104
TYPICAL PERFORMANCE CHARACTERISTICS
Step Response Falling Edge
VSENSE–
IOUT = 0µA
6V
5.5V
IOUT = –100µA
∆VSENSE– = 100mV
TA = 25°C
VS = 12V
RIN = 100Ω
1V
0.5V
RVSOEUNTS=E+5=k VS
VREF = 6V
TIME (1µs/DIV)
VOUT
6104 G19
Step Response Falling Edge
VS + 50mV
VS – 50mV
7V
VSENSE–
VOUT
4.5V
TA = 25°C
VS = 12V
RIN = 100Ω
2V RVSOEUNTS=E+5=k VS
VREF = 4.5V
TIME (1µs/DIV)
6104 G20
PSRR vs Frequency
160
140
V+ = 4V
120
V+ = 12V
100
80
60 RIN = 100Ω
40
ROUT = 5k
COUT = 5pF
GAIN = 50
20 IOUTDC = 100µA
0 VINAC = 50mVP-P
0.1 1 10 100 1k 10k 100k 1M
FREQUENCY (Hz)
6104 G20
PIN FUNCTIONS
OUT (Pin 1): Current Output. OUT will source or sink a
current that is proportional to the sense voltage into an
external resistor. A voltage reference is required to provide
the proper positive offset voltage so that the output can
swing both positive and negative.
V– (Pin 4): Negative Supply (or Ground for Single-Supply
Operation).
+INB/VS (Pin 5): The positive input of the internal sense
amplifier B. It also works as the positive supply input.
Supply current is drawn through this pin.
–INB (Pin 6): The negative input of the internal sense
amplifier B. The internal sense amplifier will drive –INB
to the same potential as +INB when VSENSE is negative.
A resistor (RIN) tied from one end of RSENSE to –INB sets
the output current IOUT = VSENSE/RIN. VSENSE is the voltage
developed across the external RSENSE (Figure 1).
–INA (Pin 7): The negative input of the internal sense
amplifier A. The internal sense amplifier will drive –INA
to the same potential as +INA when VSENSE is positive. A
resistor (RIN) tied from one end of RSENSE to –INA sets
the output current IOUT = VSENSE/RIN.
+INA (Pin 8): The positive input of the internal sense
amplifier A.
6104f
6