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PIC18F2450-I/SO View Datasheet(PDF) - Microchip Technology

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Description
Manufacturer
PIC18F2450-I/SO Datasheet PDF : 324 Pages
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PIC18F2450/4450
SUBLW
Subtract W from Literal
Syntax:
Operands:
Operation:
Status Affected:
Encoding:
Description
Words:
Cycles:
Q Cycle Activity:
Q1
Decode
SUBLW k
0 k 255
k – (W) W
N, OV, C, DC, Z
0000 1000 kkkk kkkk
W is subtracted from the 8-bit
literal ‘k’. The result is placed in W.
1
1
Q2
Read
literal ‘k’
Q3
Process
Data
Q4
Write to W
Example 1:
SUBLW 02h
Before Instruction
W
= 01h
C
=?
After Instruction
W
=
C
=
Z
=
N
=
01h
1 ; result is positive
0
0
Example 2:
SUBLW 02h
Before Instruction
W
= 02h
C
=?
After Instruction
W
=
C
=
Z
=
N
=
00h
1 ; result is zero
1
0
Example 3:
SUBLW 02h
Before Instruction
W
= 03h
C
=?
After Instruction
W
=
C
=
Z
=
N
=
FFh ; (2’s complement)
0 ; result is negative
0
1
© 2008 Microchip Technology Inc.
SUBWF
Subtract W from f
Syntax:
Operands:
Operation:
Status Affected:
Encoding:
Description:
Words:
Cycles:
Q Cycle Activity:
Q1
Decode
SUBWF f {,d {,a}}
0 f 255
d [0,1]
a [0,1]
(f) – (W) dest
N, OV, C, DC, Z
0101 11da ffff ffff
Subtract W from register ‘f’ (2’s
complement method). If ‘d’ is ‘0’, the
result is stored in W. If ‘d’ is ‘1’, the
result is stored back in register ‘f’
(default).
If ‘a’ is ‘0’, the Access Bank is
selected. If ‘a’ is ‘1’, the BSR is used
to select the GPR bank (default).
If ‘a’ is ‘0’ and the extended instruction
set is enabled, this instruction
operates in Indexed Literal Offset
Addressing mode whenever
f 95 (5Fh). See Section 19.2.3
“Byte-Oriented and Bit-Oriented
Instructions in Indexed Literal Offset
Mode” for details.
1
1
Q2
Read
register ‘f’
Q3
Process
Data
Q4
Write to
destination
Example 1:
SUBWF REG, 1, 0
Before Instruction
REG = 3
W
=2
C
=?
After Instruction
REG = 1
W
=2
C
=1
Z
=0
N
=0
; result is positive
Example 2:
SUBWF REG, 0, 0
Before Instruction
REG
W
C
=2
=2
=?
After Instruction
REG = 2
W
=0
C
=1
Z
=1
N
=0
; result is zero
Example 3:
SUBWF REG, 1, 0
Before Instruction
REG = 1
W
=2
C
=?
After Instruction
REG =
W
=
C
=
Z
=
N
=
FFh ;(2’s complement)
2
0 ; result is negative
0
1
DS39760D-page 249

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